<PRE><B>Question 147750</B>
A bicycle wheel of diameter 30 inches is spinning at a rate of 60rpm. What is the exact value of the angular velocity of the wheel in rad/min?
Ans: 60*2(pi)rad/min = 120pi rad/min
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What is the linear speed of the bicycle in the previous problem to the nearest mile per hour?
Circumference of the wheel is 30pi inches
[3600 rev/hr][30pi inches] = 108000pi inches/hr
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(108000pi in/hr)(1 ft/12 in)(1 mi/5280 ft) 

= [108000pi*1*!]/[12*5280] mph

= 5.355 mph
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Cheers,
Stan H.
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