Question 147747
1/6(log2x+log2y)-2log2(x+9)

= (1/6)log2(xy) - 2log2(x+9)

= log2(xy)^(1/6) - log2(x+9)^2

= log2[(xy)^(1/6) / (x+9)^2]

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Cheers,
Stan H.