Question 147711
1. write the equation of a line whose slope is -2 and passes through (-1,6). Write answer in slope-intercept form.
y = mx + b
y = 6 when x = -1, and m= -2 ; solve for "b":
6 = -2*-1 + b
b = 4
EQUATION:
y = -2x + 4
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2. Solve for x: (2x-7)(x+4)=0
x = 7/2 or x = -4
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3. find the vertex of f(x)=3x^2-6x+8
Vertex occurs when x = -b/2a = 6/6 = 1
f(1) = 3-6+8 = 5
Vertex: (1,5)
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4. find the y-intercept of the cubic f(x)=(x-2)(x+1)(x-3)
Let x = 0.
f(0) = -2*1*-3 = 6
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Cheers,
Stan H.