<PRE><B>Question 147659</B>
a. An financial advisor invested a total of $6,000, part at 4% annual simple interest and part at 6.5% annual simple interest. 
Amount EQUATION: x + y = 6000
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The amount of interest earned for 1 year was $335.00. How much was invested at each rate? Show work.
Interest EQUATION: 0.04x + 0.065y = 335
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Rearrange the equations:
40x + 65y = 335000
40x + 40y = 40*6000
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Subtract 2nd from 1st to get:
25y = 95000
y = $3800 (Amt. invested at 6.5%)
x = 6000 - 3800 = $2200 (Amt. invested at 4%)
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Cheers,
Stan H.
 



b. Consider the equation 3x2 – 4x + 7 = 0. 
1.Find the discriminant, b2 – 4ac, and then determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist. 



2. Use the quadratic formula to find the exact solutions of the equation. Show work. 



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