Question 147615
need help factoring these equations. 
8x^3+27y^3 
This is "the sum of cubes".
Rewrite as follows:
(2x)^3 + (3y)^3 = (2x+3y)((2x)^2 -(2x)(3y) + (3y)^2)
= (2x+3y)(4x^2 -6xy + 9y^2)
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 (x^2)(y^3)+xy
= (xy)(xy^2 + 1)

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Cheers,
Stan H.