Question 147581
Simply graph {{{R(x)=(x^3-7)/(x^2+1)}}} to get 



{{{ graph( 500, 500, -10, 10, -10, 10, (x^3-7)/(x^2+1)) }}}




and {{{R(x+2)=((x+2)^3-7)/((x+2)^2+1)}}} to get 



{{{ graph( 500, 500, -10, 10, -10, 10, ((x+2)^3-7)/((x+2)^2+1)) }}}



Together they look like this


{{{ graph( 500, 500, -10, 10, -10, 10, (x^3-7)/(x^2+1),((x+2)^3-7)/((x+2)^2+1)) }}} Graph of  {{{R(x)=(x^3-7)/(x^2+1)}}} (red) and {{{R(x+2)=((x+2)^3-7)/((x+2)^2+1)}}}(green)



So we can see that the new graph is shifted 2 units to the left.