Question 147573
If the original equation is {{{(2/3)(x-5)=9}}}, then multiply both sides by 3.  Get {{{2(x-5)=27}}}.  Then divide by two. {{{x-5=13.5}}}.  Then add five. {{{x=18.5}}}.

If the orginal equation is {{{2/3x-5=9}}}, then add five first and get {{{2/3x=14}}}. Then multiply by 3/2 and get {{{x=21}}}.