Question 147565
 

{{{3*x*y-4*x^2+y^2}}} Start with the given expression.



{{{3*(-3)*2-4*(-3)^2+(2)^2}}} Plug in {{{x=-3}}} and {{{y=2}}} 



{{{-9*2-4*(-3)^2+(2)^2}}} Multiply {{{3}}} and {{{-3}}} to get {{{-9}}}.  



{{{-18-4*(-3)^2+(2)^2}}} Multiply {{{-9}}} and {{{2}}} to get {{{-18}}}.  



{{{-18-4*9+(2)^2}}} Raise {{{-3}}} to the 2nd power to get {{{9}}}.  



{{{-18-36+(2)^2}}} Multiply {{{4}}} and {{{9}}} to get {{{36}}}.  



{{{-54+(2)^2}}} Subtract {{{36}}} from {{{-18}}} to get {{{-54}}}.  



{{{-54+4}}} Raise {{{2}}} to the 2nd power to get {{{4}}}.  



{{{-50}}} Add {{{-54}}} and {{{4}}} to get {{{-50}}}.  



So {{{3*(-3)*2-4*(-3)^2+(2)^2=-50}}} 



So {{{3*x*y-4*x^2+y^2=-50}}} when {{{x=-3}}} and {{{y=2}}}