Question 147479
center, vertices, covertices and foci of the ellipse x^2/4+y^2/9=16
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x^2/64 + y^2/144 = 1
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a = 8 ; b = 12;
c = sqrt(12^2-8^2) = sqrt(80) = 4sqrt(5)
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Center: (0,0)
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vertices: 
(0,12) ; (0,-12)
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Foci:
(0,4sqrt(5))
(0,-4sqrt(5))
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Cheers,
Stan H.