Question 147489
I don't think so.

Start with a right triangle. 
At the non-right angle vertices, double the angles. What are the resulting angles?
Let's say that one angle was alpha, then the other angle must be 90-alpha.
If we double alpha, we get 2alpha.
If we double (90-alpha), we get (180-2alpha). 
The sum of the anlges inside a triangle is 180. 
Let's add our two angles so far. 180-2alpha + 2alpha = 180. So we already have 180 degrees. The other vertex doesn't exist (the lines are parallel).