Question 147450
If grade A coffee costs .95 cents a pound and grade b coffee costs .75 cents a pound, how many pounds of each grade is needed if the total cost is $50.50, and the amount of grade b that is needed is twice the amount needed for grad A plus 5 pounds?
:
Let x = amt of grade a coffee required
:
It says,"the amount of grade b that is needed is twice the amount needed for grad A plus 5 pounds", therefore we can say:
2x + 5 = amt of grade b coffee required
:
total cost equation;
.95x + .75(2x+5) = 50.50 
:
.95x + 1.5x + 3.75 = 50.50
:
2.45x = 50.50 - 3.75
:
2.45x = 46.75
x = {{{46.75/2.45}}}
x = 19.08 lb of grade a
and
2(19.08) + 5 = 43.16.lb of grade b
:
:
Check solution on a calc:
.95(19.08) + .75(43.16) =
 18.126 + 32.37 = 50.496 ~ 50.50
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Did this make sense to you? Any questions?