Question 147428
{{{2x^2-35=15}}} Start with the given equation.



{{{2x^2=15+35}}} Add {{{35}}} to both sides.



{{{2x^2=50}}} Combine like terms on the right side.



{{{x^2=(50)/(2)}}} Divide both sides by {{{2}}} to isolate {{{x^2}}}.



{{{x^2=25}}} Reduce.



{{{x=0+-sqrt(25)}}} Take the square root of both sides.



{{{x=5}}} or {{{x=-5}}} Simplify



So our answers are {{{x=5}}} or {{{x=-5}}}