Question 147445
Given {{{6/(2-x) +6/(x+7)=61/(2-x) }}}
In this case, the first term on the left and the one on the right have the same denominator. So we can simplify them as is

{{{6/(2-x) +6/(x+7)=61/(2-x) }}}
{{{6/(x+7)=61/(2-x) - 6/(2-x) }}}
{{{6/(x+7)=(61-6)/(2-x)}}}
{{{6/(x+7)=(55)/(2-x)}}}

Now we can 'cross multiply' to get rid of the denominators on each side
{{{6*(2-x) = 55*(x+7)}}}
{{{12 - 6x = 55x + 385}}}

Now combine like terms
{{{12 - 385 = 55x + 6x }}}
{{{-(373) = 61x}}}
{{{-373/61 = x }}}