Question 147432
x2 – 7x – 1 = -7
x^2-7x+6=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}=
{{{x = (7 +- sqrt( 49-4*1*6 ))/(2) }}}=
{{{x = (7 +- sqrt(25))/(2) }}}=
{{{x = (7 +- 5)/(2) }}}

so x=6 or x= 1