Question 147367
Given {{{f(x) = 5x^2 -3x}}}
find 
f(0)
{{{f(0) = 5*(0)^2 - 3*0}}}
{{{f(0) = 0 }}}


f(-1)
{{{f(-1) = 5*(-1)^2 - 3*(-1)}}}
{{{f(-1) = 5*1 +3  }}}
{{{f(-1) = 8 }}}


f(2)
{{{f(2) = 5*(2)^2 - 3*(2)}}}
{{{f(2) = 5*4 - 6   }}}
{{{f(2) = 20 -6  }}}
{{{f(2) = 14  }}}