Question 147376
I'll do the first one to get you started.


# 1

{{{5x-y=12}}} Start with the first equation.



{{{-y=12-5x}}} Subtract {{{5x}}} from both sides.



{{{y=(12-5x)/(-1)}}} Divide both sides by {{{-1}}} to isolate {{{y}}}.



{{{y=5x-12}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=5}}} and the y-intercept is {{{b=-12}}}, which is the point (0,-12).




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{{{x+2y=9}}} Start with the second equation.



{{{2y=9-x}}} Subtract {{{x}}} from both sides.



{{{y=(9-x)/(2)}}} Divide both sides by {{{2}}} to isolate {{{y}}}.



{{{y=-(1/2)x+9/2}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/2}}} and the y-intercept is {{{b=9/2}}}, which is the point *[Tex \LARGE \left(0,\frac{9}{2}\right)].