Question 147342


{{{3x-2y-4=0}}} Start with the given equation.



{{{-2y-4=0-3x}}} Subtract {{{3x}}} from both sides.



{{{-2y=0-3x+4}}} Add {{{4}}} to both sides.



{{{-2y=-3x+4}}} Combine like terms on the right side.



{{{y=(-3x+4)/(-2)}}} Divide both sides by {{{-2}}} to isolate {{{y}}}.



{{{y=(3/2)x-2}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=3/2}}} and the y-intercept is {{{b=-2}}}, which is the point (0,-2).