Question 147343


{{{5x-4y+12=0}}} Start with the given equation.



{{{-4y+12=0-5x}}} Subtract {{{5x}}} from both sides.



{{{-4y=0-5x-12}}} Subtract {{{12}}} from both sides.



{{{-4y=-5x-12}}} Combine like terms on the right side.



{{{y=(-5x-12)/(-4)}}} Divide both sides by {{{-4}}} to isolate {{{y}}}.



{{{y=(5/4)x+3}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=5/4}}} and the y-intercept is {{{b=3}}}, which is the point (0,3).