Question 147345


{{{2x-3y+6=0}}} Start with the given equation.



{{{-3y+6=0-2x}}} Subtract {{{2x}}} from both sides.



{{{-3y=0-2x-6}}} Subtract {{{6}}} from both sides.



{{{-3y=-2x-6}}} Combine like terms on the right side.



{{{y=(-2x-6)/(-3)}}} Divide both sides by {{{-3}}} to isolate {{{y}}}.



{{{y=(2/3)x+2}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2/3}}} and the y-intercept is {{{b=2}}}, which is the point (0,2).