Question 147321
I'm assuming that you meant to write: {{{6x-4y+8=0}}}





{{{-4y+8=0-6x}}} Subtract {{{6x}}} from both sides.



{{{-4y=0-6x-8}}} Subtract {{{8}}} from both sides.



{{{-4y=-6x-8}}} Combine like terms on the right side.



{{{y=(-6x-8)/(-4)}}} Divide both sides by {{{-4}}} to isolate {{{y}}}.



{{{y=(3/2)x+2}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=3/2}}} and the y-intercept is {{{b=2}}}, which is the point (0,2).