Question 147320


{{{y-2=0-3x}}} Subtract {{{3x}}} from both sides.



{{{y=0-3x+2}}} Add {{{2}}} to both sides.



{{{y=-3x+2}}} Combine like terms on the right side.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-3}}} and the y-intercept is {{{b=2}}}, which is the point (0,2).