Question 147302
2x^2+3x+6=0
USING THE QUADRATIC EQUATION WE GET:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
X=(-3+-SQRT[3^2-4*2*6])/2*2
X=(-3+-SQRT[9-48])/4
X=(-3+-SQRT-39)/4
X=(-3+-6.245i)/4
X=-3/4+-1.56i