Question 147301
You first try to factor the quadratic:
2x^2 + 3x + 6 = 0
We need factors of 2 * 6 or 12 that sum to 3, which there are none.
The simplest way from here is to use the quadratic formula:
{{{ x = ( -b +- sqrt( b^2 - 4ac ) ) / ( 2a ) }}}
.
{{{ x = ( -3 +- sqrt( 9 - 48 ) ) / ( 4 ) }}}
The solution is imaginary because of sqrt( negative ) .. you can simplify from here.