Question 147280
In this problem, you don't necessarily need to solve for n. You just need to transform {{{4^n}}} into {{{4^(-n)}}}


{{{4^n=20}}} Start with the given equation.



{{{(4^n)^(-1)=(20)^(-1)}}} Raise both sides to the negative first power.



{{{4^(-n)=(20)^(-1)}}} Multiply the exponents on the left side.



{{{4^(-n)=1/(20^1)}}} Rewrite {{{(20)^(-1)}}} as {{{1/(20^1)}}}.



{{{4^(-n)=1/(20)}}} Simplify.