Question 147263
I'll do the first one to get you started.


A:



{{{(3b-8)/(b-6)+(b-16)/(b-6)}}} Start with the given expression.



Since the denominators are the same, we can combine the numerators over the common denominator:



{{{(3b-8+b-16)/(b-6)}}} Combine the fractions.



{{{(4b-24)/(b-6)}}} Combine like terms.



{{{(4(b-6))/(b-6)}}} Factor {{{4b-24}}} to get {{{4(b-6)}}}.



{{{(4highlight((b-6)))/(highlight(b-6))}}} Highlight the common terms. 



{{{(4cross((b-6)))/(cross(b-6))}}} Cancel out the common terms. 



{{{4}}} Simplify. 



So {{{(3b-8)/(b-6)+(b-16)/(b-6)}}} simplifies to {{{4}}}.



In other words, {{{(3b-8)/(b-6)+(b-16)/(b-6)=4}}} where {{{b<>6}}}