Question 147245

{{{x^2-13x=-12}}} Start with the given equation.



{{{x^2-13x+12=0}}} Add 12 to both sides.



{{{(x-12)(x-1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x-12=0}}} or  {{{x-1=0}}} 


{{{x=12}}} or  {{{x=1}}}    Now solve for x in each case



So our answers are 


 {{{x=12}}} or  {{{x=1}}}