Question 146924
5x-12y+33=0
5x-12y-6=0
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5x-12y+33=0
-12y=-5x-33
y=5x/12 + 33/12
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5x-12y-6=0
-12y=-5x+6
y=5x/12 - 1/2
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The distance between the parallel lines is |33/12 + 1/2|=3.25
This is easier to see if we change the slope from 5x/12 (1st graph) to 0x/12 (2nd graph)


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Ed
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{{{graph(500,500,-10,10,-10,10,(5x/12)+(33/12),(5x/12)-(1/2))}}}
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{{{graph(500,500,-10,10,-10,10,(0x/12)+(33/12),(0x/12)-(1/2))}}}