Question 22221

   Area of the recatangular closet =
             Area =LxW
              56= LxW

 SO IN OUR PROBLEM- LENGHT IS 1 FOOT MORE THAN THE WIDTH
                  SO, L= 1+W
                       WIDTH =W

    OUR NEW DIMESION IS-
                 
              AREA= LENGHT X WINDTH
                54=(1+W){W)
                54=W(1+W}
                54=W+W^2
                0=W^2+W-54
REWRITE AS    W^2+W-54=0 IN A QUADRATIC FORM.
              TO SOLVE FOR W-
FACTORISE OR  solving using Almighty quadratic fomulae to get the width
 By factorizing-
  (w+8)(w-7)=0
  w=-8 or w=7
We will have to choose 7 ,because a width cannot be negative so,so the width is 7 feet.

Therefore if width is 7 feet.
             Lenght=1+W
               L=1+7
               L=8
SO LENGHT= 8 FEET
    WIDTH= 7 FEET

MORUPH OSUOLALE
CENTRAL PIEDMONT COLLEGE,
CHARLOTTE,NC