Question 147194

{{{x^3-2x^2-4x+8}}} Start with the given expression



{{{(x^3-2x^2)+(-4x+8)}}} Group like terms



{{{x^2(x-2)-4(x-2)}}} Factor out the GCF {{{x^2}}} out of the first group. Factor out the GCF {{{-4}}} out of the second group



{{{(x^2-4)(x-2)}}} Since we have the common term {{{x-2}}}, we can combine like terms



{{{(x+2)(x-2)(x-2)}}} Factor {{{x^2-4}}} to get {{{(x+2)(x-2)}}}



{{{(x+2)(x-2)^2}}} Rewrite {{{(x-2)(x-2)}}} as {{{(x-2)^2}}}



So {{{x^3-2x^2-4x+8}}} factors to {{{(x+2)(x-2)^2}}}