Question 147158
1. for f(-1) your corresponding range should be 9, because {{{f(-1)=4(-1^2)-3(-1)+2}}}. so {{{f(-1)=4+3+2}}}. f(-1)=9. That means that when x is -1, y should be 9.

2. {{{f(x)=(x+3)/(x-1)}}}.  Your domain for this problem would be any value for x that does not make the denominator zero.  So to figure this out, just take a shortcut and find out what will make the denominator zero, and say that the domain is any value for x except that one.  In this case, to make the denominator of {{{(x+3)/(x-1)}}} zero, you would have to ask yourself, what minus one would give me zero? Of course your answer is one, so your domain would be all x except 1.