Question 147071
f(x)= -x^2+2x+5. Identify the vertex and intercept(s) 

V=(-b/2a,f(-b/2a))=(2,f(2))=(2,5)
x-intercepts: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ={{{x = (-2 +- sqrt( 2^2-4*(-1)*5 ))/(2*(-1)) }}} ={{{x = (-2 +- sqrt(24))/(-2) }}} 
y-intercepts: y=f(0)=5