Question 146888


{{{12y^3+16y^2-3y-4}}} Start with the given expression


{{{(12y^3+16y^2)+(-3y-4)}}} Group like terms



{{{4y^2(3y+4)-1(3y+4)}}} Factor out the GCF {{{4y^2}}} out of the first group. Factor out the GCF {{{-1}}} out of the second group



{{{(4y^2-1)(3y+4)}}} Since we have the common term {{{3y+4}}}, we can combine like terms



{{{(2y+1)(2y-1)(3y+4)}}} Factor {{{4y^2-1}}} to get {{{(2y+1)(2y-1)}}} by use of the difference of squares.




So {{{12y^3+16y^2-3y-4}}} factors to {{{(2y+1)(2y-1)(3y+4)}}}