Question 146880
{{{x+3=-2/x}}} Start with the given equation



{{{x*x+x*3=cross(x)(-2/cross(x))}}} Multiply <b>every</b> term by the LCD x to clear the fractions



{{{x^2+3x=-2}}} Simplify



{{{x^2+3x+2=0}}} Get all terms to the left side.



{{{(x+2)(x+1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x+2=0}}} or  {{{x+1=0}}} 


{{{x=-2}}} or  {{{x=-1}}}    Now solve for x in each case



So our answers are 


 {{{x=-2}}} or  {{{x=-1}}}