Question 146705
Using the general quadratic equation {{{ax^2+bx+c=0}}}, we can see that {{{x^2 + 6x - 5 = 0}}} can be written as {{{1x^2 + 6x +(-5) = 0}}}. So this shows us that {{{a=1}}}, {{{b=6}}} and {{{c=-5}}}