Question 146644
The answer is d, 27/13. I'm looking for a better way to solve this, but this is how I did it.

Solve for the slope and the 2 y-intercepts by putting both eqns in the form y = mx+b.
The slope of both is 5/12, and one y-int is -1/2, and the other is -11/4.
So they're 9/4 apart on the y-axis.
They form a right triangle with the X and Y axes. Since the slopes are 5/12, the sides are in the ratio of 5 (on the Y axis) to 12 (on the X axis), and the hypotenuse is 13.
Making another right triangle by connecting the 2 lines from either on the Y-intercepts gives a similar triange with the same ratios, 5, 12 and 13.
The distance between the 2 Y-intercepts is 9/4, and the long side of the triangle is 12/13 of that, so it's 12/13 times 9/4, which is 108/52, or 27/13.
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I'm sure there's a more straightforward to do this. I'll look for it, and if you email me I'll send you what I figure out.