Question 146614
{{{f(x) = 2x^3-x^2 + 3x-2}}}
{{{f(-1/2) = 2(-1/2)^3-(-1/2)^2 + 3(-1/2)-2}}}
{{{f(-1/2) = 2(-1/8)-(1/4) - (3/2)-2}}}
To add and subtract fractions, you need to have a common denominator.
Change all fraction to common denominator of 8.
{{{1/4=2/8}}}
{{{3/2=12/8}}}
{{{2=16/8}}}
{{{f(-1/2) = 2(-1/8)-(1/4) - (3/2)-2}}}
{{{f(-1/2) = (-2/8)-(2/8) - (12/8)-16/8}}}
{{{f(-1/2) = (-2-2-12-16)/8}}}
{{{f(-1/2) = (-32)/8}}}
{{{f(-1/2) = -4}}}