Question 146570
Solve using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{3x^2+7x-6 = 0}}} In this problem, a = 3, b = 7, and c = -6
Make the appropriate substitutions into the formula:
{{{x = (-7+-sqrt(7^2-4(3)(-6)))/2(3)}}} Simplify.
{{{x = (-7+-sqrt(49-(-72)))/6}}}
{{{x = (-7+-sqrt(121))/6}}}
{{{x = (-7+11)/6}}} or {{{x = (-7-11)/6}}}
{{{x = 2/3}}} or {{{x = -3}}} There are two real roots.