Question 146340

 log(a,m) + log(a,n) = log(a, m*n)

 log(12,2) + log(12,18) + log( 12,4) = x
      log (12, 2*18*4) = x
      log(12, 144) = x.

     log( m,n) =x then n= m^x.
       i.e.  144 = 12^x
             12^2 = 12^x
             i.e. x= 2.