Question 22137
i assume the 2 is the base of the log. You should explain. I shall leave the 2 out, for ease of writing...


log(x)+log(x-6)=4


To remove log-base 2, we need to raise the left and right hand terms to power 2. We can only do that easily when we have 1 term on both sides, so first we re-write the equation as:


log((x)(x-6))=4


And now we raise to power 2, giving


{{{(x)(x-6)=4^2}}}
{{{x^2-6x=16}}}
{{{x^2-6x-16 = 0}}}
(x-8)(x+2) = 0


so either x=8 or x=-2


jon.