Question 146514
{{{(4&1/3)x+1&1/2=2&1/6}}} Start with the given equation



{{{(13/3)x+3/2=13/6}}} Rewrite {{{4&1/3}}} as {{{13/3}}}. Rewrite {{{1&1/2}}} as {{{3/2}}}. Rewrite {{{2&1/6}}} as {{{13/6}}}.



{{{6((13/cross(3))x+3/cross(2))=cross(6)(13/cross(6))}}} Multiply both sides by the LCD {{{6}}} to clear any fractions.



{{{26x+9=13}}} Distribute and multiply.



{{{26x=13-9}}} Subtract {{{9}}} from both sides.



{{{26x=4}}} Combine like terms on the right side.



{{{x=(4)/(26)}}} Divide both sides by {{{26}}} to isolate {{{x}}}.



{{{x=2/13}}} Reduce.



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Answer:


So the answer is {{{x=2/13}}} 



Which approximates to {{{x=0.154}}}