Question 146413
First we look for the value that is unknown, which is the width.

So let X=width

Now, the problem states that the length is six greater than the width. 

So, let X+6= Length

The problem also tells us that the perimeter of the rectangle is 60. We also know that a rectangle as two sides that serve as the length and two sides that serve as the width. In order to solve this, we must add the widths and the lengths together and make them equal to 60.

Remember, X = Width and X+6= Width.

So, X + X + X + 6 + X + 6 = 60

Then we combine like terms: 4X+12=60

Subtract 12 from both sides.

4X=48

Divide by four to get rid of the X.

X=12

Now we plug 12 into our length and width formulas which were X and X+6.

Width=12
Length=18