Question 146267


{{{3x+2y-2=0}}} Start with the given equation.



{{{2y-2=0-3x}}} Subtract {{{3x}}} from both sides.



{{{2y=0-3x+2}}} Add {{{2}}} to both sides.



{{{2y=-3x+2}}} Combine like terms on the right side.



{{{y=(-3x+2)/(2)}}} Divide both sides by {{{2}}} to isolate {{{y}}}.



{{{y=-(3x)/(2)+(2)/(2)}}} Break up the fraction.



{{{y=(-3/2)x+1}}} Reduce.




So the equation is now in slope-intercept form ({{{y=mx+b}}}) where the slope is {{{m=-3/2}}} and the y-intercept is {{{b=1}}}