Question 2506
[(1*(x))/((x-1)*(x))]+[(2*(x-1))/((x)*(x-1))]=[((x)*(x))/((x-1)*(x))]

[(3x-2)/(x^2-x)]=[(x^2)/(x^2-x)]
3x-2=x^2
x^2-3x+2=0
(x-2)(x-1)=0
x-2=0 => x=2; x-1=0 => x=1