Question 146262

{{{96x^2-6y^2}}} Start with the given expression



{{{6(16x^2-y^2)}}} Factor out the GCF {{{6}}}



{{{6(4x+y)(4x-y)}}} Now use the difference of squares to factor {{{16x^2-y^2}}} to get {{{(4x+y)(4x-y)}}}



So {{{96x^2-6y^2}}} factors to {{{6(4x+y)(4x-y)}}}