Question 146189
[(x+3/x+1)-2]/(x-1)

To simplify the bracket you need a common denominator:

= [(x+3)/(x+1) - 2(x+1)/(x+1)] / (x-1)

Now combine the numerators in the bracket to get:

= [(x+3 -2x-2)/(x+1)] /(x-1)

= [(-x+1)/(x+1)]/(x-1) 

Now, invert the denominator and change to multiplication:

= [-(x-1)/(x+1)] * [ 1/(x-1)]

Cancel any factor that is common to a numerator and a denominator to get:

= [-1/(x+1)]*[1/(x-1)]

= -1/(x^2-1)

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Cheers,
Stan H.
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