<PRE><B>Question 146138</B>
One canned juice drink is 15% orange juice; another is 5% orange juice. How many liters of each should be mixed together in order to get 10L that is 8% orange juice?
How many liters of the 15% orange juice should be in the mixture?
Let x = amt of 15% o.j required
:
The resulting mixture is to be 10l, therefore:
(10-x) = amt of 5% o.j.
:
% orange juice equation
.15x = .05(10-x) = .08(10)
.15x + .5 - .05x = .8
.15x - .05x = .8 - .5
.10x = .3
x = {{{.3/.1}}}
x = 3 liters of 15% o.j.
:
How many liters of the 5% ORANGE juice should be in the mixture?
10 - 3 = 7 liters of 5% o.j.
:
:
Check solution
.15(3) + .05(7) =
.45 + .35 = .08(10)</PRE>