Question 146104
-2k^0-4k+6(-k-2^0)-(-5k)=-(2-5)k-4k 
-2-4k-6k-6+5k=-(-3k)-4k Any number to ^0=1.
-5k-8=3k-4k
-5k-8=-k
-4k=8
k=-2
.
Ed