Question 146120
In words:
(pounds of fat)/(total pounds) = 1%
Let {{{n}}}= pounds of no-fat yogurt to be added
Let {{{r}}}= pounds of 3% fat yogurt to be added
It is given that
{{{n + r = 60}}}
also
{{{.03r/60 = .01}}}
{{{.03r =  .6}}}
{{{r = 20}}}
{{{n + r = 60}}}
{{{n = 40}}}
20 pounds of regular yogurt and 40 pounds of no-fat yogurt should be
mixed to obtain 60 pounds of low fat yogurt.
check answer:
{{{.03r/60 = .01}}}
{{{.03*20/60 = .01}}}
{{{.03*20 = .6}}}
{{{.6 = .6}}}
OK