Question 146121
Let {{{y}}}= probability they play in Superbowl
Let {{{n}}}= probability they do not
{{{y + n = 1}}}
{{{y = 9n}}}
{{{9n + n = 1}}}
{{{10n = 1}}}
{{{n = 1/10}}}
{{{y + (1/10) = 1}}}
{{{y = 1 - (1/10)}}}
{{{y = 9/10}}}
The probability they play in next Superbowl is 9/10