Question 146081
The complex conjugate of a complex number, (a+bi) is just (a-bi), so for:
{{{(3-i)}}} the complex conjugate is (3+i) and the product of these two can be found using the FOIL method:
{{{(3-i)(3+i) = 9+3i-3i-i^2}}} Simplify the product:
{{{9-i^2}}} Substitute {{{i^2 = -1}}}
{{{9-(-1) = 9+1}}} = {{{10}}}
Answer C: (3+i), 10